C Program to find the leap year using if-else statement

Write a program to find the leap year in C Language?

Before writing a C program for leap year, let’s see what is Leap year and what is the logic behind, to write a program.Leap year has 366 days in year with 29 days in February.It is a year which comes once every 4 years.

Logic:
If a year is perfectly divisible by 4, it means that is a leap year and If the year can be evenly divided by 100, it is NOT a leap year, unless the year is also evenly divisible by 400. Then it is a leap year.To understand more about the logic for leap year, read Leap year article at Wikipedia.

Here is source code of the C program to check a given year is leap year:

#include<stdio.h>
int divide(int num)
{
if(num%4==0)
{
printf(“%d is leap year”,num);
}
else
{
printf(“%d is not a leap year”,num);
}
return (num);
}
int main()
{
int a;
printf(“enter the value of a”);
scanf(“%d”,&a);
divide(a);
return 0;
}

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